NIMCET 2027 Computer Memory Back-up Devices Previous Year Questions (PYQs) – Page 3 of 3
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Consider a hard disk with 16 recording surfaces (0-15) having 16384 cylinders (0-16383) and each cylinder contains 64 sectors(0-63). Data storage capacity in each sector is 512 bytes. Data are organized cyclinderwise and the addressing format is . A file of size 42797KB is stored in the disk and the starting disk location of the file is <1200,9,40>. What is cylinder number of the last sector of the file, if it is stored in a contiguous manner?
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A hard disk has a rotational speed of 6000 rpm. Its average latency time is
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The capacity of a memory unit is defined by the number of words multiplied by the number of bits per word. How many separate address and data line are needed for a memory of 4K × 16?
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4K = $2^{12}$ words → 12 address lines
Word size = 16 bits → 16 data lines
A hard drive system has $2$ circular disks with a total of $4$ surfaces. The disk has $5000$ tracks, each with $2000$ sectors. How many sectors can be read without the reading head having to make a mechanical movement?
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Solution
Without mechanical movement of the reading head, the system can read sectors from the same cylinder.
A cylinder consists of the same track number across all surfaces.
Given:
Number of surfaces $=4$
Sectors per track $=2000$
So, sectors readable without head movement:
$4\times 2000=8000$
NIMCET 2027
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