TANCET MCA 2024 Previous Year Questions (PYQs) – Page 1 of 10
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Showing 96 questions
Which of the following is not an example of word formation process called blending?
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Solution
Motel, moped, eurocrat are blends.
Automate is not a blended word.
If Rakesh borrows Rs. 36,000 from Sathesh at rate of interest 6% S.I. at the end of four years, how much interest Rakesh has to pay?
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Solution
Simple interest $= frac{P imes R imes T}{100}$
$= frac{36000 imes 6 imes 4}{100}$
$= 8640$
Hence, the required interest is Rs. 8,640.
$= frac{36000 imes 6 imes 4}{100}$
$= 8640$
Hence, the required interest is Rs. 8,640.
A train moving at 108 km/hr crosses a platform in 30 seconds. Then it crosses a man running at 12 km/hr in the same direction to train in 9 seconds. What is the length of train and platform in m?
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Solution
Speed of train $= 108 imes frac{5}{18} = 30$ m/s
Speed of man $= 12 imes frac{5}{18} = frac{10}{3}$ m/s
Relative speed $= 30 - frac{10}{3} = frac{80}{3}$ m/s
Length of train $= frac{80}{3} imes 9 = 240$ m
Train length + platform length $= 30 imes 30 = 900$ m
Platform length $= 900 - 240 = 660$ m
Hence, the answer is 240 and 660.
Speed of man $= 12 imes frac{5}{18} = frac{10}{3}$ m/s
Relative speed $= 30 - frac{10}{3} = frac{80}{3}$ m/s
Length of train $= frac{80}{3} imes 9 = 240$ m
Train length + platform length $= 30 imes 30 = 900$ m
Platform length $= 900 - 240 = 660$ m
Hence, the answer is 240 and 660.
Two trains are moving towards each other with speeds 50 km/hr and 55 km/hr from different stations R and S. While they meet, the second train from station S has covered 20 km more distance than the first train which starts from station R. What is the distance between the two stations?
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Solution
Distances are proportional to speeds.
Ratio $= 50:55 = 10:11$
Difference $= 1$ part $= 20$ km
Total distance $= 21 imes 20 = 420$ km
Hence, the distance is 420 km.
Ratio $= 50:55 = 10:11$
Difference $= 1$ part $= 20$ km
Total distance $= 21 imes 20 = 420$ km
Hence, the distance is 420 km.
50 men can paint a building in 15 days working 4 hours a day. In how many days 40 men working 5 hours a day will complete the work?
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Solution
Total work $= 50 imes 15 imes 4 = 3000$ man-hours
$40 imes 5 imes x = 3000$
$200x = 3000$
$x = 15$
Hence, required time is 15 days.
$40 imes 5 imes x = 3000$
$200x = 3000$
$x = 15$
Hence, required time is 15 days.
Anish and Bala can do a work in 8 days, Bala and Cynthia can do the same work in 12 days. Anish, Bala and Cynthia finish it together in 6 days. How many days A and C will together do it?
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Solution
$A+B=frac{1}{8}$, $B+C=frac{1}{12}$, $A+B+C=frac{1}{6}$
$B=frac{1}{8}+frac{1}{12}-frac{1}{6}=frac{1}{24}$
$A+C=frac{1}{6}-frac{1}{24}=frac{1}{8}$
Hence, required time is 8 days.
$B=frac{1}{8}+frac{1}{12}-frac{1}{6}=frac{1}{24}$
$A+C=frac{1}{6}-frac{1}{24}=frac{1}{8}$
Hence, required time is 8 days.
Reena and Shaloo are partners in a business. Reena invests Rs.35,000 for 8 months and Shaloo invests Rs.42,000 for 10 months. Out of profit of Rs.31,570, Reena’s share is
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Solution
Ratio $= 35000 imes 8 : 42000 imes 10 = 280000 : 420000 = 2:3$
Reena share $= frac{2}{5} imes 31570 = 12628$
Reena share $= frac{2}{5} imes 31570 = 12628$
A started a business with Rs.21,000 and is joined afterwards by B with Rs.36,000. After how many months did B join if the profit at the end of the year is divided equally?
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Solution
$21000 imes 12 = 36000 imes x$
$252000 = 36000x$
$x=7$ months before end
So join after $12-7=5$ months
$252000 = 36000x$
$x=7$ months before end
So join after $12-7=5$ months
A, B and C enter into a partnership in the ratio $\frac{7}{2} : \frac{4}{3} : \frac{6}{5}$. After 4 months, A increases his share by 50%. If the total profit at the end of one year is Rs.21,600 then B’s share is
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Solution
Effective ratio $= 35:10:9$
B share $= frac{10}{54}×21600 = 4000$
B share $= frac{10}{54}×21600 = 4000$
If 4(A’s capital) = 6(B’s capital) = 10(C’s capital), then out of profit of Rs.4,650 C will receive
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Solution
Ratio $= \frac{1}{4}:\frac{1}{6}:\frac{1}{10} = 15:10:6$
C share $= \frac{6}{31}×4650 = 900$
C share $= \frac{6}{31}×4650 = 900$
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