TANCET MCA Time And Work Previous Year Questions (PYQs)
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50 men can paint a building in 15 days working 4 hours a day. In how many days 40 men working 5 hours a day will complete the work?
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Solution
Total work $= 50 imes 15 imes 4 = 3000$ man-hours
$40 imes 5 imes x = 3000$
$200x = 3000$
$x = 15$
Hence, required time is 15 days.
$40 imes 5 imes x = 3000$
$200x = 3000$
$x = 15$
Hence, required time is 15 days.
Anish and Bala can do a work in 8 days, Bala and Cynthia can do the same work in 12 days. Anish, Bala and Cynthia finish it together in 6 days. How many days A and C will together do it?
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Solution
$A+B=frac{1}{8}$, $B+C=frac{1}{12}$, $A+B+C=frac{1}{6}$
$B=frac{1}{8}+frac{1}{12}-frac{1}{6}=frac{1}{24}$
$A+C=frac{1}{6}-frac{1}{24}=frac{1}{8}$
Hence, required time is 8 days.
$B=frac{1}{8}+frac{1}{12}-frac{1}{6}=frac{1}{24}$
$A+C=frac{1}{6}-frac{1}{24}=frac{1}{8}$
Hence, required time is 8 days.
Two pipes can fill a cistern in 14 hour and 16 hour respectively. The pipes are opened simultaneously and due to leakage it took extra time. When full, in what time will leak empty it?
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Solution
Answer $=112$ hour
A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
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Solution
Ratio $1:2:4$ ⇒ A takes 35 hr
Pipes A and B can fill a tank in 5 and 6 hour respectively. Pipe C can empty it in 12 hour. If all three pipes are opened together then the tank will be filled in
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Solution
Net $=17/60$ ⇒ Time $=60/17=3\frac{9}{17}$
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