WB JECA MCA 2024 Previous Year Questions (PYQs) – Page 1 of 8
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What is the output of the following code snippet?
#include <stdio.h>
main() {
int x = 65, *p = &x;
void *q = p;
char *r = q;
printf("%c", *r);
}
(A) $A$
(B) $Z$
(C) $65$
(D) None of the above
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Solution
Step 1: Initialization
$x = 65$
In ASCII, $65 \equiv A$
Step 2: Pointer flow
$p = \&x \;\; \rightarrow$ pointer to integer
$q = p \;\; \rightarrow$ void pointer
$r = q \;\; \rightarrow$ typecast to char pointer
Step 3: Dereferencing
Since r is char*, it reads 1 byte.
The value stored = $65$
Step 4: Printing
printf("%c", *r); prints character with ASCII $65$.
Hence, the output is:
$\; \boxed{A} \;$
Correct Answer: (A)
ROM is a
(A) Combinational Circuit
(B) Static Circuit
(C) Sequential Circuit
(D) Magnetic Circuit
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Solution
- ROM (Read Only Memory) stores fixed data permanently.
- Its output depends only on the given input address.
- No clock or feedback is required, so it is not sequential.
- Hence, ROM is a Combinational Circuit.
Correct Answer: (A) Combinational Circuit
Each stage in pipelining should be completed within _________cycles.
(A) 1
(b) 2
(C) 3
(D) 4
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Solution
- In pipelining, the CPU instruction is divided into stages (Fetch, Decode, Execute, etc.).
- To maximize throughput, each stage must complete within 1 clock cycle.
- This ensures that new instructions can enter the pipeline without delay.
Correct Answer: (A) 1
Relational calculus is a
(A) Procedural language
(B) Non-procedural language
(C) Data definition language
(D) High-level language
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Solution
- Relational Algebra is procedural (it specifies how to obtain the result).
- Relational Calculus is non-procedural (it specifies what to obtain, not how).
Correct Answer: (B) Non-procedural language
How many parameters does a default constructor require ?
(A) 1
(B) 2
(C) 0
(D) 3
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Solution
- A default constructor in C++ is a constructor that takes no arguments.
- It is invoked automatically when an object is created without passing parameters.
Correct Answer: (C) 0
An artificially intelligent car decreases its speed based on its distance from the car in front of it. Which method is used?
- (A) Naive Bayes
- (B) Decision Tree
- (C) Linear Regression
- (D) Logistic Regression
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Solution
- The car’s speed is a continuous variable that depends on the distance from the car ahead.
- To model this relation, we need a method for predicting a continuous outcome.
Correct Answer: (C) Linear Regression
The keyword friend does not appear in
(A) the class allowing access to another class.
(B) the class desiring access to another class.
(C) the private section of a class.
(D) the public section of a class.
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Solution
- The
friendkeyword is used inside a class definition to allow another class or function to access its private/protected members. - It appears in the class granting access (not the one desiring access).
- It can be declared in either public or private section of that class.
Correct Answer: (B) the class desiring access to another class
What is the maximum number of level-2 DFD possible if the number of
processes in level-1 DFD is n ?
(A) $\frac{n}{2}$
(B) 2
(C) $n^2$
(D) n
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Solution
- In a Data Flow Diagram (DFD), each process in level-1 can be decomposed further into its own level-2 diagram.
Correct Answer: (D) $n$
The small extremely fast RAM's are termed as ______
(A) Heap
(B) Accumulators
(C) Stack
(D) Cache
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Solution
- Heap → Memory area for dynamic allocation.
- Accumulator → Register in CPU for intermediate results.
- Stack → Memory area used for function calls and local variables.
- Cache → Small, high-speed RAM located close to the CPU, used to store frequently accessed data.
Correct Answer: (D) Cache
A computer with a 32 bit wide data bus uses 4k × 8 static RAM memory chips. The smallest memory this computer is
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Solution
Each RAM chip = $4k \times 8 = 32k$ bits = 4 KB.
Bus width = 32 bits, each chip = 8 bits → need 4 chips in parallel.
Total memory = $4 \times 4$ KB = 16 KB.
Answer = (B) 16 kb
Bus width = 32 bits, each chip = 8 bits → need 4 chips in parallel.
Total memory = $4 \times 4$ KB = 16 KB.
Answer = (B) 16 kb
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