CUET PG MCA Ratio Proportion And Variation Previous Year Questions (PYQs)
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In a class, 4/5 of the students are boys and rest are girls. If 2/5 of the boys and 1/4 of girls are absent, what part of the total number of students is present?
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Solution
Solution
Given: 4/5 of the students are boys, and the rest are girls. 2/5 of boys and 1/4 of girls are absent.
Step-by-Step Solution
- Total students =
N - Boys:
(4/5) × N = 4N/5 - Girls:
(1/5) × N = N/5 - Boys absent:
(2/5) × (4N/5) = 8N/25 - Girls absent:
(1/4) × (N/5) = N/20 - Boys present:
(4N/5 - 8N/25 = 12N/25) - Girls present:
(N/5 - N/20 = 3N/20) - Total present =
(12N/25 + 3N/20)
Final Calculation
LCM of 25 and 20 is 100:
(12N/25 = 48N/100), (3N/20 = 15N/100)
Total present = (48N/100 + 15N/100 = 63N/100)
Answer: 63/100
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