Let y = y(x) be the solution of the differential equation ${{dy} \over {dx}} = 1 + x{e^{y - x}}, - \sqrt 2 < x < \sqrt 2 ,y(0) = 0$ then, the minimum value of $y(x),x \in \left( { - \sqrt 2 ,\sqrt 2 } \right)$ is equal to :
Let y = y(x) be the solution of the differentialequationcosx${{dy} \over {dx}}$ + 2ysinx = sin2x, x $ \in $ $\left( {0,{\pi \over 2}} \right)$.Ify$\left( {{\pi \over 3}} \right)$ = 0, then y$\left( {{\pi \over 4}} \right)$ is equal to :
Let a curve $y=f(x)$ pass through the points $(0,5)$ and $(\log_e 2,\,k)$. If the curve satisfies the differential equation $2(3+y)e^{2x}\,dx-(7+e^{2x})\,dy=0$, then $k$ is equal to:
Let $y=y(x)$ be the solution of the differential equation $(3y^{2}-5x^{2})\,y\,dx+2x\,(x^{2}-y^{2})\,dy=0$ such that $y(1)=1$. Then $\left|(y(2))^{3}-12y(2)\right|$ is equal to:
Let $f:[0,\infty)\to\mathbb{R}$ be a differentiable function such that
$f(x)=1-2x+\displaystyle\int_{0}^{x}e^{,x-t}f(t),dt$ for all $x\in[0,\infty)$.
Then the area of the region bounded by $y=f(x)$ and the coordinate axes is
If the solution $y = y(x)$ of the differential equation
$(x^{4}+2x^{3}+3x^{2}+2x+2)\,dy-(2x^{2}+2x+3)\,dx=0$
satisfies $y(-1)=-\dfrac{\pi}{4}$, then $y(0)$ is equal to:
If \(\dfrac{dy}{dx}+\dfrac{3}{\cos^2 x}\,y=\dfrac{1}{\cos^2 x},\ x\in\left(-\dfrac{\pi}{3},\dfrac{\pi}{3}\right)\) and \(y\!\left(\dfrac{\pi}{4}\right)=\dfrac{4}{3}\), then \(y\!\left(-\dfrac{\pi}{4}\right)\) equals:
Let $f(x)=
\begin{cases}
x^{3}-x^{2}+10x-7, & x\le 1,\\
-2x+\log_{2}(b^{2}-4), & x>1.
\end{cases}$
Then the set of all values of $b$ for which $f(x)$ has maximum value at $x=1$ is:
The general solution of the differential equation$\sqrt {1 + {x^2} + {y^2} + {x^2}{y^2}} $ + xy${{dy} \over {dx}}$ = 0 is : (where C is a constant of integration)