CUET UG Mathematics Applied Time And Work Previous Year Questions (PYQs)
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A pipe can empty $\left(\frac{5}{6}\right)$th part of a cistern in 20 minutes.
The part of cistern which will be empty in 9 minutes is:
1
2
3
4
Solution
Pipe empties $\frac{5}{6}$ part in 20 minutes.
Rate per minute
$=\frac{5}{6} \div 20$
$=\frac{5}{6}\times \frac{1}{20}$
$=\frac{5}{120}$
$=\frac{1}{24}$
So in 1 minute it empties $\frac{1}{24}$ part.
In 9 minutes:
$=\frac{9}{24}$
$=\frac{3}{8}$
CUET UG Mathematics Applied
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CUET UG Mathematics Applied
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