Jamia Millia Islamia MCA Arithmetic Reasoning Previous Year Questions (PYQs) – Page 1 of 2
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If 7 parallel lines are intersected by another set of 7 parallel lines, the number of parallelograms formed is:
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Solution
Number of parallelograms formed = ${}^{7}C_{2} \times {}^{7}C_{2}$
= (21 × 21) = 441.
Jamia Central Library has 510 visitors on Sundays and 240 visitors on other days.
The average number of visitors per day in a 30-day month beginning with a Sunday is:
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Solution
Number of Sundays in 30 days starting with Sunday = 5
Visitors on Sundays = 5 × 510 = 2550
Visitors on other 25 days = 25 × 240 = 6000
Total visitors = 8550
Average = 8550 ÷ 30 = 285
Select the ODD number from the given alternatives:
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Solution
Check perfect cubes:
2197 = 13³
3375 = 15³
2744 = 14³
4099 ❌ not a perfect cube
If A stands for ADD, B for SUBTRACT, C for MULTIPLY and D for DIVIDE, then find the value of 2A3B4D2.
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Solution
$2A3B4D2 = 2+3-4\div 2 = 5-2 = 3 $
When two coins are tossed simultaneously, what is the probability of getting at least one tail?
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Solution
Total outcomes = HH, HT, TH, TT
Favourable outcomes for at least one tail = HT, TH, TT
$P(\text{at least one tail}) = \tfrac{3}{4}$
The total of the ages of Amar, Akbar and Anthony is 80 years.
What was the total of their ages three years ago?
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Solution
Three years ago, each of the three persons was 3 years younger.
So, total age decreased by $3 \times 3 = 9$ years.
Hence, $80 - 9 = 71$ years.
$\boxed{\text{Answer: (A) 71 years}}$
If + means ÷, x means –, – means × and ÷ means +,
then find the value of $38 + 19 – 16 × 17 ÷ 3$.
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Solution
Given meanings:
$+ \rightarrow ÷,\; × \rightarrow –,\; – \rightarrow ×,\; ÷ \rightarrow +$
So, expression becomes:
$38 ÷ 19 × 16 – 17 + 3$
= $(38 ÷ 19) × 16 – 17 + 3$
= $2 × 16 – 17 + 3 = 32 – 17 + 3 = 18$
$\boxed{\text{Answer: (C) 18}}$
If $54 + 43 = 2$, $60 + 51 = 10$, $70 + 61 = 12$, then $72 + 62 = ?$
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Solution
Add digits of each number and then multiply:
For $54 + 43 \Rightarrow (5+4)+(4+3)=9+7=16$, 1+6=7−5=2 pattern → next → $72+62\Rightarrow 9+8=17$, 1+7=8+1=9? ≈ pattern → $\boxed{13}$
A shepherd had 27 sheep. All but 10 died. How many he left with?
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Solution
All but 10 died means $10$ are alive.
If $54+43=2,\ 60+51=10$, then $62+72=\ ?$
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Solution
Rule: $(ab)+(cd)\ \mapsto\ (a-b)+(c-d)$ (sum of digit-differences).
$54+43 \Rightarrow (5-4)+(4-3)=1+1=2$.
$60+51 \Rightarrow (6-0)+(5-1)=6+4=10$.
$62+72 \Rightarrow (6-2)+(7-2)=4+5=9$.
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