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Jamia Millia Islamia MCA Data Representation - Number System Previous Year Questions (PYQs) – Page 1 of 2
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Jamia Millia Islamia MCA Data Representation - Number System Previous Year Questions (PYQs) – Page 1 of 2
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Jamia Millia Islamia MCA
Previous Year Questions
Jamia Millia Islamia MCA
Previous Year Questions
Jamia Millia Islamia MCA
Qus : 1
2
The decimal equivalent of $(0.101)_2$ will be —
1
0.5
2
0.625
3
0.25
4
0.875
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Discussion
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Solution
$(0.101)_2 = (1×2^{-1}) + (0×2^{-2}) + (1×2^{-3}) = 0.5 + 0 + 0.125 = 0.625$
Qus : 2
2
How many bytes are required to encode 2000 bits of data?
1
1
2
2
3
3
4
8
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Video Solution
Discussion
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Solution
1 byte = 8 bits So, $2000 \text{ bits} = \dfrac{2000}{8} = 250$ bytes.
Qus : 3
1
The pair byte and nibble comprise of ...... bit(s) respectively.
1
8 and 4
2
4 and 6
3
8 and 6
4
4 and 8
View Solution
Video Solution
Discussion
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Solution
1 byte = 8 bits 1 nibble = 4 bits
Qus : 4
1
What is the name of the data metric used to refer to the size $10^{24}$ ?
1
Yotta
2
Zetta
3
Exa
4
Giga
View Solution
Video Solution
Discussion
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Solution
$10^{24}$ bytes = 1 Yottabyte. The prefix "Yotta" represents $10^{24}$.
Qus : 5
3
The hexadecimal subtraction of $(56)_{16}$ from $(427)_{16}$ results in:
1
$(3B1)_{16}$
2
$(331)_{16}$
3
$(371)_{16}$
4
$(3D1)_{16}$
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Discussion
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Solution
$(427)_{16} - (56)_{16} = (371)_{16}$
Qus : 6
4
In which numbering system can the binary number 1011011111000101 be easily converted to?
1
Decimal system
2
Gray
3
Octal system
4
Hexadecimal system
View Solution
Video Solution
Discussion
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Solution
Grouping binary in 4 bits maps directly to hex.
Qus : 7
2
$8\,\text{GB}$ is equal to:
1
$2^{30}$ bytes
2
$2^{33}$ bytes
3
$2^{20}$ bytes
4
$2^{23}$ bytes
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Discussion
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Solution
Zing is not a search engine.
Qus : 8
4
Convert (231)_4 into (____)_3.
1
1102
2
1201
3
1100
4
1200
View Solution
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Discussion
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Solution
(231)_4 = 2·4^2 + 3·4 + 1 = 45_(10).
45 to base 3 → 1·3^3 + 2·3^2 + 0·3 + 0 = 1200_3.
Qus : 9
1
Convert (1278)_12 into (____)_4.
1
200330
2
220330
3
12302
4
200300
View Solution
Video Solution
Discussion
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Solution
(1278)_12 = 1·12^3 + 2·12^2 + 7·12 + 8 = 2108_(10).
2108 to base 4:
= 2·4^5 + 0·4^4 + 0·4^3 + 3·4^2 + 3·4 + 0 = 200330_4.
Qus : 10
3
Convert (110100)_2 into (____)_16
1
CD
2
43
3
34
4
D
View Solution
Video Solution
Discussion
✓
Solution
110100₂ = 0011 0100₂ = 3 4₁₆ →
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