Jamia Millia Islamia MCA Letter Series Previous Year Questions (PYQs)
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Showing 9 questions
fill the missing terms marked by question marks
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Solution
Solution:
Work column-wise with a constant step of −8 in alphabet positions (A=1,…,Z=26):
Col1: Z(26) → R(18) → ? ⇒ 26−8=18−8=10 ⇒ J
Col2: ? → O(15) → G(7) ⇒ top must be 23 ⇒ W
Col3: S(19) → ? → C(3) ⇒ middle must be 11 ⇒ K
Thus the three letters (top-middle, middle-right, bottom-left) are W, K, J → “WKJ”.
Next term of the series: $A1B,\; BD2,\; D3G,\; GK4,\; \ldots$ ?
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Solution
Left letters $A,B,D,G,K$ with steps $+1,+2,+3,+4$ → next $+5$: $K$ stays as left? (already K from prev step), actually pattern gives next pair $K\to P$ and right $B,D,G,K\to P$; number $1,2,3,4\to5$.
So $K5P$.
$\boxed{K_5P}$
Next term of the series: $C1Z,\; D3Y,\; E5X,\; F7W,\; \ldots$ ?
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Solution
Left $C,D,E,F\to G$; numbers $1,3,5,7\to 9$; right $Z,Y,X,W\to V$.
Needed $G9V$ — not in options.
Next term of the series: $ABZ,\; BDY,\; DFX,\; GHW,\; \ldots$ ?
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Solution
First letters $A,B,D,G$ with jumps $+1,+2,+3$ → next $+4$: $K$.
Second letters $B,D,F,H$ ($+2$ each) → $J$.
Third letters $Z,Y,X,W$ ($-1$ each) → $V$.
$\boxed{\text{KJV}}$
Next term of the series: $CAT,\; EBS,\; GCR,\; IDQ,\; \ldots$ ?
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Solution
First letters $C,E,G,I\to K$ ($+2$); second $A,B,C,D\to E$ ($+1$); third $T,S,R,Q\to P$ ($-1$).
$\boxed{\text{KEP}}$
Find the missing terms of this series:
b, a, a, b, ?, a, b, a, ?, b, b, a, ?, ?
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Solution
Solution:
Look at odd and even positions separately.
Odd positions (1,3,5,7,9,11,13): b, a, ?, b, ?, b, ? → pattern = "bab" repeating ⇒ 5=b, 9=a, 13=b.
Even positions (2,4,6,8,10,12,14): a, b, a, a, b, a, ? → pattern = "aba" repeating ⇒ 14=a.
Missing terms (in order 5th, 9th, 13th, 14th) = b, a, b, a → **baba**.
Complete the series:
Z, L, X, J, V, H, T, F, __, __
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Solution
Solution:
Two interleaved sequences:
- 1st,3rd,5th,7th,…: Z(26), X(24), V(22), T(20) ⇒ decreasing by 2 ⇒ next = R(18).
- 2nd,4th,6th,8th,…: L(12), J(10), H(8), F(6) ⇒ decreasing by 2 ⇒ next = D(4).
So the next two letters are **R, D**.
A letter series is given with blanks:
$C\_\ BBA\_\ CAB\_\ AC\_\ AB\_\ AC$
The missing letters (left to right) are given by which option?
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Solution
Filling with **ACBCB** gives
$C\color{blue}{A}BBA\color{blue}{C}CAB\color{blue}{B}AC\color{blue}{C}AB\color{blue}{B}AC$
Grouping in 3’s: $[CAB][BAC][CAB][BAC][CAB]$ — a neat repetition of the block “CAB, BAC”.
Other choices break this pattern.
The missing term in the sequence ADVENTURE, DVENTURE, DVENTUR, ____, VENTU is:
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Solution
Alternating deletions: drop first, then last letter.
ADVENTURE → (drop A) DVENTURE → (drop E) DVENTUR → (drop D) VENTUR → (drop R) VENTU.
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