Jamia Millia Islamia MCA Probability PNC Previous Year Questions (PYQs)
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Three numbers are chosen from 1 to 20.
Find the probability that they are consecutive.
1
2
3
4
Solution
Total ways = $\binom{20}{3} = 1140$
Consecutive triplets: (1,2,3), (2,3,4), …, (18,19,20) → 18 sets.
Required probability $= \dfrac{18}{1140} = \dfrac{3}{190}$
$\boxed{\text{Answer: (D) }\dfrac{18}{\binom{20}{3}}}$
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