Aspire Faculty ID #11519 · Topic: NIMCET 2023 · Just now
NIMCET 2023

The locus of the mid-point of all chords of the parabola $y^2 = 4x$ which are drawn through its vertex is

Solution

Locus of Midpoint of Chords

Given Parabola: \( y^2 = 4x \)

Condition: Chords pass through the vertex \( (0, 0) \)

Let the other end of the chord be \( (x_1, y_1) \), so the midpoint is:

\( M = \left( \frac{x_1}{2}, \frac{y_1}{2} \right) = (h, k) \)

Since the point lies on the parabola: \( y_1^2 = 4x_1 \)

⇒ \( (2k)^2 = 4(2h) \)

⇒ \( 4k^2 = 8h \)

⇒ \( \boxed{k^2 = 2h} \)

✅ Locus of midpoints: \( y^2 = 2x \)

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