Aspire Faculty ID #12184 · Topic: JEE Main 2021 (24 February Morning Shift) · Just now
JEE Main 2021 (24 February Morning Shift)

The function $f(x) = {{4{x^3} - 3{x^2}} \over 6} - 2\sin x + \left( {2x - 1} \right)\cos x$ :

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