Aspire Faculty ID #12243 · Topic: JEE Main 4 September 2020 (Evening) · Just now
JEE Main 4 September 2020 (Evening)

Let $f:\left( {0,\infty } \right) \to \left( {0,\infty } \right)$ be a differentiable function such that f(1) = e and
$\mathop {\lim }\limits_{t \to x} {{{t^2}{f^2}(x) - {x^2}{f^2}(t)} \over {t - x}} = 0$. If f(x) = 1, then x is equal to :

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