Aspire Faculty ID #12294 · Topic: JEE Main 6 September 2020 (Morning) · Just now
JEE Main 6 September 2020 (Morning)

If $\sum\limits_{i = 1}^n {\left( {{x_i} - a} \right)} = n$ and $\sum\limits_{i = 1}^n {{{\left( {{x_i} - a} \right)}^2}} = na$(n, a > 1) then the standard deviation of n observations x1, x2, ..., xn is :

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