Aspire Faculty ID #12733 · Topic: JEE Main 2021 (31 August Evening Shift) · Just now
JEE Main 2021 (31 August Evening Shift)

If ${{dy} \over {dx}} = {{{2^x}y + {2^y}{{.2}^x}} \over {{2^x} + {2^{x + y}}{{\log }_e}2}}$, y(0) = 0, then for y = 1, the value of x lies in the interval :

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