Aspire Faculty ID #12747 · Topic: JEE Main 2021 (1 September Evening Shift) · Just now
JEE Main 2021 (1 September Evening Shift)

The function $f(x) = {x^3} - 6{x^2} + ax + b$ is such that $f(2) = f(4) = 0$. Consider two statements : Statement 1 : there exists x1, x2 $\in$(2, 4), x1 < x2, such that f'(x1) = $-$1 and f'(x2) = 0. Statement 2 : there exists x3, x4 $\in$ (2, 4), x3 < x4, such that f is decreasing in (2, x4), increasing in (x4, 4) and $2f'({x_3}) = \sqrt 3 f({x_4})$.Then

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