Aspire Faculty ID #12845 · Topic: JEE Main 2022 (24 June Morning Shift) · Just now
JEE Main 2022 (24 June Morning Shift)

If $\{ {a_i}\} _{i = 1}^n$, where n is an even integer, is an arithmetic progression with common difference 1, and $\sum\limits_{i = 1}^n {{a_i} = 192} ,\,\sum\limits_{i = 1}^{n/2} {{a_{2i}} = 120} $, then n is equal to :

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