Aspire Faculty ID #12883 · Topic: JEE Main 2022 (25 June Evening Shift) · Just now
JEE Main 2022 (25 June Evening Shift)

$\mathop {\lim }\limits_{x \to {\pi \over 2}} \left( {{{\tan }^2}x\left( {{{(2{{\sin }^2}x + 3\sin x + 4)}^{{1 \over 2}}} - {{({{\sin }^2}x + 6\sin x + 2)}^{{1 \over 2}}}} \right)} \right)$ is equal to

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