Aspire Faculty ID #12942 · Topic: JEE Main 2022 (27 June Evening Shift) · Just now
JEE Main 2022 (27 June Evening Shift)

The set of values of k, for which the circle $C:4{x^2} + 4{y^2} - 12x + 8y + k = 0$ lies inside the fourth quadrant and the point $\left( {1, - {1 \over 3}} \right)$ lies on or inside the circle C, is :

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