Aspire Faculty ID #12953 · Topic: JEE Main 2022 (28 June Morning Shift) · Just now
JEE Main 2022 (28 June Morning Shift)

Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral $\int\limits_0^1 {[ - 8{x^2} + 6x - 1]dx} $ is equal to :

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