Aspire Faculty ID #12957 · Topic: JEE Main 2022 (28 June Morning Shift) · Just now
JEE Main 2022 (28 June Morning Shift)

Let y = y(x) be the solution of the differential equation $x(1 - {x^2}){{dy} \over {dx}} + (3{x^2}y - y - 4{x^3}) = 0$, $x > 1$, with $y(2) = - 2$. Then y(3) is equal to :

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