Aspire Faculty ID #12999 · Topic: JEE Main 2022 (29 June Evening Shift) · Just now
JEE Main 2022 (29 June Evening Shift)

If $\int\limits_0^2 {\left( {\sqrt {2x} - \sqrt {2x - {x^2}} } \right)dx = \int\limits_0^1 {\left( {1 - \sqrt {1 - {y^2}} - {{{y^2}} \over 2}} \right)dy + \int\limits_1^2 {\left( {2 - {{{y^2}} \over 2}} \right)dy + I} } } $, then I equals

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