Aspire Faculty ID #13119 · Topic: JEE Main 2022 (28 July Evening Shift) · Just now
JEE Main 2022 (28 July Evening Shift)

The function $f : \mathbb{R} \to \mathbb{R}$ defined by $$ f(x) = \lim_{n \to \infty} \frac{\cos(2 \pi x) - x^{2n} \sin(x-1)}{1 + x^{2n+1} - x^{2n}} $$ is continuous for all $x$ in :

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