Aspire Faculty ID #13166 · Topic: JEE Main 2023 (24 January Morning Shift) · Just now
JEE Main 2023 (24 January Morning Shift)

Let $y=y(x)$ be the solution of the differential equation $x^{3}\,dy+(xy-1)\,dx=0,\quad x>0,$ with $y\!\left(\dfrac{1}{2}\right)=3-e.$ Then $y(1)$ is equal to:

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