Aspire Faculty ID #13369 · Topic: JEE Main 2023 (8 April Morning Shift) · Just now
JEE Main 2023 (8 April Morning Shift)

$ \text{Let } C(\alpha,\beta) \text{ be the circumcenter of the triangle formed by the lines } 4x+3y=69,; 4y-3x=17,; x+7y=61. $ $ \text{Then } (\alpha-\beta)^2+\alpha+\beta \text{ is equal to:} $

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