Aspire Faculty ID #13386 · Topic: JEE Main 2023 (8 April Evening Shift) · Just now
JEE Main 2023 (8 April Evening Shift)

The numbers $\alpha>\beta>0$ are the roots of the equation $a x^{2}+b x+1=0$, and $\displaystyle \lim_{x\to \frac{1}{\alpha}} \left( \frac{1-\cos!\big(x^{2}+bx+a\big)}{2(1-a x)^{2}} \right)^{\tfrac{1}{2}} = \frac{1}{k}!\left(\frac{1}{\beta}-\frac{1}{\alpha}\right).$ Then $k$ is equal to:

Previous 10 Questions — JEE Main 2023 (8 April Evening Shift)

Nearest first

Next 10 Questions — JEE Main 2023 (8 April Evening Shift)

Ascending by ID
Ask Your Question or Put Your Review.

loading...