Aspire Faculty ID #13454 · Topic: JEE Main 2023 (12 April Morning Shift) · Just now
JEE Main 2023 (12 April Morning Shift)

Let $\alpha, \beta$ be the roots of the quadratic equation $x^{2}+\sqrt{6}x+3=0$. Then $\dfrac{\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}}$ is equal to:

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