Aspire Faculty ID #13743 · Topic: JAMIA MILLIA ISLAMIA MCA 2022 · Just now
JAMIA MILLIA ISLAMIA MCA 2022

For real numbers $x,y$, define $x\,R\,y$ iff $x-y+\sqrt{2}$ is irrational. Then the relation $R$ is:

Solution

For reflexivity: $xRx$ means $x-x+\sqrt{2}=\sqrt{2}$ (irrational) ⇒ true. For symmetry: $xRy⇒x-y+\sqrt{2}$ irrational, but $y-x+\sqrt{2}=-(x-y)+\sqrt{2}$ may be rational. Not always true ⇒ not symmetric. For transitivity: fails similarly.

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