Aspire Faculty ID #13868 · Topic: JAMIA MILLIA ISLAMIA MCA 2021 · Just now
JAMIA MILLIA ISLAMIA MCA 2021

Three persons A, B, and C fire at a target in turn, starting with A. Their probabilities of hitting the target are $0.4,\ 0.3,\ 0.2$ respectively. The probability of exactly two hits is:

Solution

**Solution:** Let $A,B,C$ denote hitting events. Probability of exactly 2 hits: \[ P = P(A,B,\bar{C}) + P(A,\bar{B},C) + P(\bar{A},B,C) \] $= (0.4)(0.3)(0.8) + (0.4)(0.7)(0.2) + (0.6)(0.3)(0.2)$ $= 0.096 + 0.056 + 0.036 = 0.188$ $\boxed{\text{Answer: (B) 0.188}}$

Previous 10 Questions — JAMIA MILLIA ISLAMIA MCA 2021

Nearest first

Next 10 Questions — JAMIA MILLIA ISLAMIA MCA 2021

Ascending by ID
Ask Your Question or Put Your Review.

loading...