Aspire Faculty ID #13970 · Topic: JAMIA MILLIA ISLAMIA MCA 2020 · Just now
JAMIA MILLIA ISLAMIA MCA 2020

The equation of the circle with centre $(0, 2)$ and radius $2$ is...

Solution

Equation of circle: $(x - h)^2 + (y - k)^2 = r^2$ Substitute $(h, k) = (0, -2)$ and $r = 2$: $x^2 + (y + 2)^2 = 4 \Rightarrow x^2 + y^2 + 4y = 0.$

Previous 10 Questions — JAMIA MILLIA ISLAMIA MCA 2020

Nearest first

Next 10 Questions — JAMIA MILLIA ISLAMIA MCA 2020

Ascending by ID
Ask Your Question or Put Your Review.

loading...