Aspire Faculty ID #14166 · Topic: JEE Main 2024 (29 January Morning Shift) · Just now
JEE Main 2024 (29 January Morning Shift)

Let $A$ be a square matrix such that $AA^{\mathrm T}=I$. Then $\dfrac12\,A\Big[(A+A^{\mathrm T})^{2}+(A-A^{\mathrm T})^{2}\Big]$ is equal to:

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