Aspire Faculty ID #14308 · Topic: JEE Main 2024 (1 February Evening Shift) · Just now
JEE Main 2024 (1 February Evening Shift)

Consider $10$ observations $x_{1},x_{2},\ldots,x_{10}$ such that $\displaystyle \sum_{i=1}^{10}(x_{i}-\alpha)=2$ and $\displaystyle \sum_{i=1}^{10}(x_{i}-\beta)^{2}=40$, where $\alpha,\beta$ are positive integers. Let the mean and the variance of the observations be $\dfrac{6}{5}$ and $\dfrac{84}{25}$ respectively. Then $\dfrac{\beta}{\alpha}$ is equal to:

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