Aspire Faculty ID #14649 · Topic: JEE Main 2025 (24 January Evening Shift) · Just now
JEE Main 2025 (24 January Evening Shift)

If $\alpha>\beta>\gamma>0$, then the expression $\cot ^{-1}\left\{\beta+\frac{\left(1+\beta^2\right)}{(\alpha-\beta)}\right\}+\cot ^{-1}\left\{\gamma+\frac{\left(1+\gamma^2\right)}{(\beta-\gamma)}\right\}+\cot ^{-1}\left\{\alpha+\frac{\left(1+\alpha^2\right)}{(\gamma-\alpha)}\right\}$ is equal to :

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Topic: JEE Main 2025 (24 January Evening Shift)
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