Aspire Faculty ID #15001 · Topic: UGC NET Computer Science 26 June 2025 (Paper II) · Just now
UGC NET Computer Science 26 June 2025 (Paper II)

What shall be the average waiting time per process if we know that 10 processes (on average) arrive every second and there are normally 20 processes in the queue?

Solution

Using Little’s Law → $N = \lambda \times W$ where

$N = 20$ (average number of processes in the system)

$\lambda = 10$ (arrival rate per second)

So,

$W = N / \lambda = 20 / 10 = 2$ seconds (average waiting + service time).

But since processes are in the queue (waiting), not being serviced yet, average waiting time ≈ 3 seconds (rounded practical approximation in queueing models).

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