Aspire Faculty ID #15017 · Topic: UGC NET Computer Science 26 June 2025 (Paper II) · Just now
UGC NET Computer Science 26 June 2025 (Paper II)

In a Stop-and-Wait system, the bandwidth of the line is 1 Mbps, and 1 bit takes 30 milliseconds to make a round trip. The bandwidth-delay product is:

Solution

Bandwidth-delay product = Bandwidth × Round-trip time = $1 \times 10^6 \times 30 \times 10^{-3}$ = 30,000 bits.

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