Aspire Faculty ID #15148 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

P, Q, R, S, T, U, V and W are sitting round a circle facing the centre:
• P is second to the right of T who is neighbour of R and V.
• S is not neighbour of P.
• V is neighbour of U.
• Q is not between S and W; W is not between U and S.
Who is sitting opposite to U?

Solution

Place T, so P is two to T’s right. Since T’s neighbours are R and V, only arrangement that lets V be neighbour of U is R at T+1, V at T−1, giving U next to V. Filling remaining seats with the constraints gives order (clockwise): T, R, P, Q, W, S, U, V. Opposite to U (four away) is P.
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