Aspire Faculty ID #15400 · Topic: MAH MCA CET 2023 · Just now
MAH MCA CET 2023

Line intersect on the hyperbola at points $(-2,-6)$ and $(4,2)$, and their asymptotes are $(1,-2)$. Then the centre of the hyperbola is

Solution

Midpoint of intersecting points $(-2,-6)$ and $(4,2)$ gives centre: $\left(\dfrac{-2+4}{2}, \dfrac{-6+2}{2}\right) = (1,-2)$.
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