Aspire Faculty ID #15719 · Topic: JEE Main 2019 (12 January Evening Shift) · Just now
JEE Main 2019 (12 January Evening Shift)

If   A = $\left[ {\matrix{ 1 & {\sin \theta } & 1 \cr { - \sin \theta } & 1 & {\sin \theta } \cr { - 1} & { - \sin \theta } & 1 \cr } } \right]$;

then for all $\theta $ $ \in $ $\left( {{{3\pi } \over 4},{{5\pi } \over 4}} \right)$, det (A) lies in the interval :

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