Aspire Faculty ID #15740 · Topic: JEE Main 2019 (8 April Morning Shift) · Just now
JEE Main 2019 (8 April Morning Shift)

Let $y=y(x)$ be the solution of the differential equation $(x^2+1)^2\dfrac{dy}{dx}+2x(x^2+1)y=1$ such that $y(0)=0$. If $\sqrt{a,y(1)}=\dfrac{\pi}{32}$, then the value of $a$ is:

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If $\alpha$ and $\beta$ be the roots of the equation $x^2-2x+2=0$, then the least value of $n$ for which $\left(\dfrac{…
Topic: JEE Main 2019 (8 April Morning Shift)
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A point on the straight line $3x+5y=15$ which is equidistant from the coordinate axes will lie only in:
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Topic: JEE Main 2019 (8 April Morning Shift)
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Topic: JEE Main 2019 (8 April Morning Shift)
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Topic: JEE Main 2019 (8 April Morning Shift)
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If $f(x)=\dfrac{2-x\cos x}{2+x\cos x}$ and $g(x)=\log_e x,\ (x>0)$, then the value of the integral $\displaystyle \int_…
Topic: JEE Main 2019 (8 April Morning Shift)
8
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Topic: JEE Main 2019 (8 April Morning Shift)
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Topic: JEE Main 2019 (8 April Morning Shift)
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Topic: JEE Main 2019 (8 April Morning Shift)

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