Aspire Faculty ID #15944 · Topic: JEE Main 2018 (Offline) · Just now
JEE Main 2018 (Offline)

If $\displaystyle \sum_{i=1}^{9}(x_i-5)=9$ and $\displaystyle \sum_{i=1}^{9}(x_i-5)^{2}=45$, then the standard deviation of the $9$ items $x_1,x_2,\ldots,x_9$ is :

Previous 10 Questions — JEE Main 2018 (Offline)

Nearest first

Next 10 Questions — JEE Main 2018 (Offline)

Ascending by ID
Ask Your Question or Put Your Review.

loading...