Aspire Faculty ID #15995 · Topic: JEE Main 2017 (Offline) · Just now
JEE Main 2017 (Offline)

If for $x\in\left(0,\dfrac14\right)$, the derivative of $\tan^{-1}\left(\dfrac{6x\sqrt{x}}{1-9x^{3}}\right)$ is $\sqrt{x}\cdot g(x)$, then $g(x)$ equals :

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