Aspire Faculty ID #16174 · Topic: NIMCET 2011 · Just now
NIMCET 2011

If $\displaystyle \sum_{K=0}^{2n}(-1)^K\binom{2n}{K}^2 = A$, find $\displaystyle \sum_{K=0}^{2n}(-1)^K(K-2n)\binom{2n}{K}^2$.

Solution

$\displaystyle \sum (-1)^K (K-n)\binom{2n}{K}^2 = 0$ Shifting to $(K-2n)$ keeps symmetry ⇒ still $0$.

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