Aspire Faculty ID #16533 · Topic: NIMCET 2008 · Just now
NIMCET 2008

The value of $\displaystyle \int_0^{\pi/2} \frac{dx}{1+\tan^3 x}$ is

Solution

Using property $\int_0^{\pi/2} f(\tan x)dx = \int_0^{\pi/2} f(\cot x),dx$ 
Add both: $I=\int_0^{\pi/2} \frac{1}{1+\tan^3 x}dx$ 
$I=\int_0^{\pi/2} \frac{\tan^3 x}{1+\tan^3 x}dx$ 
$2I=\int_0^{\pi/2}1dx=\frac{\pi}{2}$ 
$I=\frac{\pi}{4}$

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