Aspire Faculty ID #16548 · Topic: NIMCET 2008 · Just now
NIMCET 2008

In the expression $(x+1)(x+4)(x+9)(x+16)\cdots(x+400)$ the coefficient of $x^{19}$ is

Solution

Coefficient of $x^{19}$ equals sum of constants: $1+4+9+\cdots+400$ This is sum of squares from $1^2$ to $20^2$: $\frac{20(21)(41)}{6}=2870$ Answer: $\boxed{2870}$

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