Aspire Faculty ID #16841 · Topic: AMU MCA 2024 · Just now
AMU MCA 2024

A polygon has 9 diagonals. Then the number of sides of the polygon is:

Solution

Number of diagonals of a polygon $= \frac{n(n-3)}{2}$ $\frac{n(n-3)}{2} = 9$ $n(n-3) = 18$ $n^2 - 3n - 18 = 0$ $(n-6)(n+3) = 0$ $n = 6$

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