Aspire Faculty ID #17054 · Topic: AMU MCA 2021 · Just now
AMU MCA 2021

Consider a noise less channel with bandwidth of 3000 Hz transmitting a signal with two signal levels. Maximum bit rate can be

Solution

Using Nyquist Formula: $C = 2B \log_2 M$ Here $B = 3000$, $M = 2$ $C = 2 \times 3000 \times \log_2 2$ $= 6000 \times 1$ $= 6000$ bps

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