Aspire Faculty ID #17079 · Topic: AMU MCA 2021 · Just now
AMU MCA 2021

The solution of the differential equation $ \dfrac{d^2y}{dx^2} - 2\dfrac{dy}{dx} + y = xe^x \sin x $

Solution

Auxiliary equation: $ m^2 - 2m + 1 = 0 $ $ (m-1)^2 = 0 $ So CF: $ y_c = (c_1 + c_2 x)e^x $ Particular integral gives: $ y_p = e^x(2\cos x + x\sin x) $ Therefore, $ y = (c_1 + c_2 x)e^x + e^x(2\cos x + x\sin x) $

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