Aspire Faculty ID #17272 · Topic: CUET UG 2022 Applied Mathematics · Just now
CUET UG 2022 Applied Mathematics

Corner points of the feasible region for an LPP are
$(0,2),; (3,0),; (6,0)$ and $(6,8)$.

If $z=2x+3y$ is the objective function of LPP then
$\max(z)-\min(z)$ is equal to:

Solution

Evaluate $z=2x+3y$ at each corner point:

At $(0,2)$
$z=2(0)+3(2)=6$

At $(3,0)$
$z=2(3)+3(0)=6$

At $(6,0)$
$z=2(6)+0=12$

At $(6,8)$
$z=2(6)+3(8)=12+24=36$

So,

$\max(z)=36$

$\min(z)=6$

Therefore,

$\max(z)-\min(z)=36-6=30$
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