Aspire Faculty ID #17887 · Topic: JEE Main 2026 (21 January Morning Shift) · Just now
JEE Main 2026 (21 January Morning Shift)

The number of relations, defined on the set ${a,b,c,d}$, which are both reflexive and symmetric, is equal to:

Solution

Set has 4 elements → total pairs = $4 \times 4 = 16$

Reflexive condition:
All $(a,a), (b,b), (c,c), (d,d)$ must be present → fixed

Remaining pairs = $16 - 4 = 12$

Symmetric condition:

Pairs form symmetric pairs like:
$(a,b)$ with $(b,a)$ → 1 choice pair

Total such independent pairs = $\frac{12}{2} = 6$

Each pair → 2 choices (present or not)

Total relations:

$ = 2^6 = 64 $

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